Algebra 1 Chapter 5 vocab
Terms
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- consecutive even
- even intergers that differ by 2 units
- consecutive intergers
- intergers that follow one another
- factoring the sum and diff of two cubes
- F cubed + L cubed = (f+l)(f2-FL+L2)
- factoring tris with lead coefficients other than 1
- factor out any GCF. write trinomial as product of 2 bis. If c is positive signs should match sign of b. if c is negative, signs within bi are opposing. guess. if no combo works= prime. check by multiplication
- key number
- the last constant number that is the easiest to work everything else arround
- prime trinomial
- a trinomial with interger coefficiants cannot be factored using only intergers
- Factoring out the GCF
- When you pull the GCF out of a polynomial. So 12x+3 is 3(4x+1)
- The opposite of the GCF
- Write each term of the polynomial as the product of -10 and another factor
- difference of two cubes
- a cubed - 64b cubed
- factoring method for solving a quadratic equation
- write in standard form, factor the left hand side. use zero factor property, solve each resulting equation, check the results
- sum of two squares
- x2+4= (x+2)(x+2)
- interchange
- put each in the place of the other
- zero factor property
- when the product of two real numbners is 0 at least one of them is 0.
- pythagoreon theorum
- a2+b2=c2
- Factored completely
- no factor can be factored further
- hypotenuse
- longest side of a right triangle
- factoring trinomials by grouping
- factor any GCF. Identify AB and C and find the key number AC. Find two numbers whos products is key nuber. Enter the two numbers as coefficients o x between the 1st and last terms and factor
- Greatest common factor
- of a list or of intergers, it is the largest fact of the two
- perfect interger squares
- numbers that have a square
- trial and check method
- guess and check
- lead coefficiant
- coefficiant of the squared variable
- quadratic equation
- an equation that can be written in standard form ax2+bx+c
- Factoring by grouping
- Group the terms of the poly so the first two have a common factor and the last two have a common factor. Factor common from each group. Factor out resulting binomial factor, regroup terms and repeat
- perfect square trinomials
- trinomials that are squares of binomials
- factor tris with x2+bx+c
- identify b and the key number, find 2 numbers whos product is key number and whos sum is b, enter the two numbers as coefficients of x in the form below, then factor
- sum of two cubes
- x cubued +8
- difference of two squares
- x squared - y squared
- stategy for finding GCG
- 1. Write each coefficient as a product of Prime Numbers 2. identify the numerical and variable factors common to each term 3. Multiply the common factors identified in step 2 to obtain the GCF
- right triangle
- a triangle that has a 90 degree angle