Suppose 8Mn=1 (-1)^(n+1)an is an alternating series. If 1)0(lt)a[n+1](lt)a[n] for every n, and lim a[n] = 0, then (-1)^(n+1)converges
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Angle between u and v
u.v = |u||v| cos(())
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Area through vectors
A = 1\\2|u||v|sin(()) = 1\\2|uxv|
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Comparison Test - convergence
M an and M bn are positive-term series, if Mbn converges and an(lt)bn for every n, then an converges
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Comparison Test - divergence
M an and M bn are positive-term series, if bn diverges and an > bn for every n, then an diverges
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Comparison Test examples
p/(q+k) < p/q < (p+k)/q, try to simplify to geometric or p-series
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Decreasing function
if f\'(x) < 0 OR bottom increases while top doesn\'t
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Definition of Absolutely Convergent
both MAn and M|An| converges
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Definition of Conditionally Convergent
MAn converges but M|An| diverges (only on Alternating Series and by Limit Comparison or Integral and Alternating Series Test)
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Dot Product of v and u
u1v1+u2v2+...
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Estimate f(x)
f(x) = Pn(x) + Rn(x) for some z betseen x and a
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Harmonic Series
8Mk=1 1/k = 1+1/2+1/3+1/4+..., which diverges
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Integral Test
8Mn=1 an, 1~8 f(x)dx = lim(t->8) 1~t f(x)dx, if 8Mn=1 an is a positive-term series and f is a continous positive-valued, decreasing (eventually) function for eacn n = 1, 2, 3, etc.
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Limit Comparison Test
Suppose An and Bn are positive-term series;
1)If lim An/Bn = L with 0(lt)L(lt)8, then either both converge or both diverge
2)if lim An\\Bn = 0 and Bn converges, An converges
3) If lim An\\Bn = 8 and Bn diverges, then An diverges